Question

I GIVE MEDALS.

The soccer player is running at a speed of 4 m/s when he slides on the ground, coming to a stop in a distance of 2 m. What was his acceleration?

Answer 1

u=4 v=0 S=2

Use v^2-u^2= 2aS

Answer 2

so it's 0^2-4^2=2a(2)?
how would i solve for acceleration? @AravindG

Answer 3

Simplify on both sides

Answer 4

do i need tom move the equation around to make it where it says "a="? @AravindG

Answer 5

Yep

Answer 6

You could divide by 4 on both sides to get a

Answer 7

okay, so i got this far.
0^2-4^2=2a(2)
=-16=2a(2)
=-4=2a(2)

is this correct so far?
how would i solve for the other side?
@AravindG

Answer 8

Yeah right

Now divide by 4 on both sides

Answer 9

how would divide the right side with a variable in it? @AravindG

Answer 10

\[\dfrac{-4}{4}=\dfrac{4a}{4}\]

Answer 11

Simple as that

Answer 12

so the final answer would be -1=1a? @AravindG

Answer 13

Yep ie a=-1 :)

Answer 14

thanks so much! @AravindG

Answer 15

yw :)