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MEDAL The sum of 1/9, 2/3, and 5/18is A. 12/9. B. 4/15. C. 19/18. D. 8/30.
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@ZambieMan
\[\frac{ 1 }{ 9 } + \frac{ 2 }{ 3 } + \frac{ 5 }{ 18 }\] \[(\frac{ 1 }{ 9})\frac{ 2 }{ 2 } + (\frac{ 2 }{ 3 })\frac{ 3 }{ 3 } + \frac{ 5 }{ 18 }\]
\[\frac{ 2 }{ 18 } + \frac{ 6 }{ 18 } + \frac{ 5 }{ 18 }\]
@StudyGurl14 has made all the denominators common, ie 18
\[\frac{ 13 }{ 18 }\]
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This way we can add all the numerators.
is that correct?
Yup :)
hurrah!!
Hey Hey wait
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Its wrong
Sorry to crash the party
it is?
that wasn't even an answer choice ha
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