I will give you a medal+ fan if you answer it right now :) How would you graph the solution to x/3 ≤ -2? Draw a closed circle on -6 and shade to the right. Draw a closed circle on -6 and shade to the left. Draw an open circle on -6 and shade to the right. Draw an open circle on -6 and shade to the left.
???
Draw a closed circle on -6 and shade to the left.
yes that is what i thought
how do u do that lol im bad at math
can u see my graph?
no
i attached it at the first response
it wont let me go onto it
ok but i dont get it
≤ means x/3 is less than or equal to -2
I'll draw how it'll look on a graph if you still don't understand.
so what would it be a)Draw a closed circle on -6 and shade to the right. b)Draw a closed circle on -6 and shade to the left. c)Draw an open circle on -6 and shade to the right. d)Draw an open circle on -6 and shade to the left.
I've already said b, draw a closed circle on -6 and shade it to the left.
How would you graph the solution to x/3 ≤ -2? i have drawn both y=x/3 (in blue) and y=-2 (in red).. what the question is asking is shade in the region in which y=x/3 is LESS THAN OR EQUAL to -2. So u then shade in the region where there are lesser values than or equal to -2. now we draw a closed circle on that shaded area beause we are including -2
thx @marigirl @moondisyko
happy to help!
:) @marigirl
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