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1/8=4^8x+2
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Just want to make sure this is the equation you want to solve: \(\large \dfrac{1}{8} = 4^{8x+2}\).
You will do this one just like the last one. Think of 1/8 as \[2^{-3}\] and 4 as \[2^{2}\]
yeah that's the equation
so it would be -3=2(8x+2) ?
Yes, that would be correct. So what do you get when you solve for x?
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[\frac{ -7 }{ 16 }\]
-7/16
Yes, that's correct. Does this process make more sense now?
yes it does. thanks
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