Question

find the polynomial function with -1/2, -2, 3

Answer 1

assuming those are the roots?
\({\bf -\cfrac{1}{2}, -2, 3\implies x=\{-\cfrac{1}{2}, -2, 3\}}\\ \quad \\

\begin{array}{llll}
x=-\cfrac{1}{2}\implies x+\cfrac{1}{2}=0\implies &\left(x+\cfrac{1}{2}\right)=0\\ \quad \\
x=-2\implies =0\implies &(x+2)=0\\ \quad \\
x=3\implies x-3=0\implies &(x-3)=0
\end{array}\\ \quad \\\implies \bf \left(x+\cfrac{1}{2}\right)(x+2)(x-3)=0
\)

Answer 2

hmmm \({\bf -\cfrac{1}{2}, -2, 3\implies x=\{-\cfrac{1}{2}, -2, 3\}}\\ \quad \\

\begin{array}{llll}
x=-\cfrac{1}{2}\implies x+\cfrac{1}{2}=0\implies &\left(x+\cfrac{1}{2}\right)=0\\ \quad \\
x=-2\implies x+2=0\implies &(x+2)=0\\ \quad \\
x=3\implies x-3=0\implies &(x-3)=0
\end{array}\\ \quad \\\implies \bf \left(x+\cfrac{1}{2}\right)(x+2)(x-3)=0\)

so multiply the "roots" to get the polynomial

Answer 3

thank you i really appreciate it

Answer 4

yw