Question

Find x: 2-1/3(3x-9)^3=0

Answer 1

\[2-\frac{1}{3}(3x-9)^3=0\]

Answer 2

Is that the problem?

Answer 3

Yes

Answer 4

1. Subtract 2 from both sides.
2. Multiply both sides by -3
3. Take the third root of both sides
4. Add 9 to both sides
5. Divide both sides by 3

Answer 5

I got 4.26 as an answer but in the textbook it has 3.6

Answer 6

\[\frac{-1}{3}(3x-9)^3=-2\]
\[(3x-9)^3=8\]
\[3x-9=2\]
\[3x=11\]
\[x=\frac{11}{3}=3 \frac{2}{3}=3.666666666....\]

Answer 7

Where did you get the 8 from?

Answer 8

What i did was multiplying the -2 with 3

Answer 9

yep. I made a mistake. It should be 6

Answer 10

\[(3x-9)^3=6\]
\[3x-9=\sqrt[3]{6}\]
\[x-3=\frac{\sqrt[3]{6}}{3}\]
\[x=3+\frac{\sqrt[3]{6}}{3}\]

Answer 11

I did it a different way

Answer 12

I only did that because I don't have my calculator with me.

Answer 13

-1/3(3x-9)^3 = -2
-(3x-9)^3 = -6
-3(x-3)^3 = -6
(x-3)^3 = 2

Answer 14

you cannot factor that 3 out.

Answer 15

Why?

Answer 16

Since it is raised to a power?

Answer 17

yes