Can someone tell me if this is correct
for this problem 12y-15/25y^2-4
(5y-4)(5y+4) Factoring the denominator
5y-4=0 Equal to zero
5y+4=0 Equal to zero
5y=4 5y= -4 Addition and Subtraction to both sides
y-4/5 y=-4/5 Divide both sides with 5
So my domain will be the expression of a set of all Real numbers excluding +4/5 and -4/5.
this is for Domain of rational expression

Question

Can someone tell me if this is correct 
for this problem 12y-15/25y^2-4
(5y-4)(5y+4)  Factoring the denominator
5y-4=0   Equal to zero
5y+4=0  Equal to zero
5y=4   5y= -4 Addition and Subtraction to both sides
y-4/5    y=-4/5  Divide both sides with 5
So my domain will be the expression of a set of all Real numbers excluding +4/5 and -4/5.  
this is for Domain of rational expression

loser66 · Answer

yup

anonymous · Answer

I actually did this correct?

loser66 · Answer

yup

anonymous · Answer

Thank you for the encouragement.

loser66 · Answer

I did nothing , just confirm your already correct answer

anonymous · Answer

Can you tell me if this other one is correct also

anonymous · Answer

5m^2 + m / 7m
                                          

Step 1. Set the denominator equal to 0.   7m= 0
 Step 2. Solve for m.   m= 0
 Step 3. m cannot equal that value.   m ≠ 0 
 0 is the excluded value in the domain for this expression.

loser66 · Answer

to me, it's good enough to get A

anonymous · Answer

You are awesome thank you so much.

loser66 · Answer

:)