Mathematics
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OpenStudy (anonymous):
Please help I fan and give medals!
If f(x) varies directly with x2, and f(x) = 96 when x = 4, find the value of f(2).
A.192
B.72
C.32
D.24
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OpenStudy (anonymous):
@ParthKohli AHHH! I NEED YOUR SMARTNESS!
Parth (parthkohli):
Again, we have an equation f(x) = c * x^2
OpenStudy (anonymous):
Right can you walk me through it?
Parth (parthkohli):
Sorry... OK, so first let's find c.
Parth (parthkohli):
We can make out
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Parth (parthkohli):
c from the given data above
OpenStudy (anonymous):
f(2)=c times x^2
Parth (parthkohli):
So for x = 4, we have f(x) = 96. Let's plug that in the original equation:
96 = c * (4)^2
Parth (parthkohli):
Solve for c.
OpenStudy (anonymous):
um how do I do that I probably sound realy dumb right now. :(
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Parth (parthkohli):
What is 4^2?
OpenStudy (anonymous):
16
OpenStudy (anonymous):
then what?
Parth (parthkohli):
96 = c * 16
OpenStudy (anonymous):
right
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Parth (parthkohli):
c = 6
OpenStudy (anonymous):
how?
Parth (parthkohli):
96 = c * 16
Divide both sides by 16
OpenStudy (anonymous):
ok now what do I do?
Parth (parthkohli):
So you finally have f(x) = 6x^2. Use it to get f(2)
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OpenStudy (anonymous):
then?
OpenStudy (anonymous):
I'm sorry I'm just really confused on this whole thing. :(
Parth (parthkohli):
I'm sorry. It's a pain to type on my phone. I promise i can do better on the laptop.
OpenStudy (anonymous):
oh its ok
Parth (parthkohli):
f(2) = 6 * (2)^2
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OpenStudy (anonymous):
f(2)=24?
Parth (parthkohli):
Yus!
OpenStudy (anonymous):
ok so then thats my answer?
OpenStudy (anonymous):
@ParthKohli
Parth (parthkohli):
Yes
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OpenStudy (anonymous):
ok thanks again can I bother you one more time to check one of my answers?