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Find the roots of the polynomial equation x^3-x^2+x+39
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A 1+3i,1-3i,-3 B 1+3i, 1-3i,3 C -2+3i, -2-3i, -3 D 2+3i,2-3i,-3
well use the factor theorem to start f(-3) = 0 so x = -3 is a zero, then some polynomial division since x = -3 is a zero, then x + 3 is a factor so |dw:1389299922916:dw| so then f(x) = (x +3)(x^2 -4x + 13) you just need the general quadratic formula to solve the quadratic.. hope it helps
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