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Find the roots of the polynomial equation
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\[x ^{3}-4x ^{2}+x+26\]
A) 3+2i, 3-2i, -2 B) 3+2i, 3-2i, 2 C) -3+2i, -3 -2i, 2 D) -3 +2i, -3-2i,-2
the roots, so you need to set it equal zero first. \[x^3-4x^2+x+26=0\] the possible roots are going to be positive and negative factors of 26. \[1,~-1,~~~2,~-2,~~~13,~-13,~~~~26,~~-26.\] which of these numbers work?
Step 1: use synthetic division and test 2 and -2 (the choices in the answer only offer those two) then use the quadratic formula to find the remaining 2 roots of the quadratic you get from step 1.
Yeah I don't get it....
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Factors that work are -1, 26; 1 -26; 2 -13; -13 2
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