Please Help I will fan and give medals!!!:)
Write the quadratic variation equation for the relationship:
y varies directly with x2 and y = 36 when x = 3.
A.y = 12x
B.y = ¼x2
C.y = 4x2
D.y = x2 + 25
@ranga
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OpenStudy (ranga):
"y varies directly with x^2" implies
y = k * x^2 ---- (1)
When x = 3, y = 36
Plug the values into equation (1) and solve for k.
OpenStudy (anonymous):
36=k*9
OpenStudy (anonymous):
then I should divide each side bye 9?
OpenStudy (ranga):
Yes. Divide each side by 9 to solve for k.
OpenStudy (anonymous):
so 4=k?
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OpenStudy (ranga):
yes, k = 4. Put k in the equation y = k * x^2 and see which answer choice represents the equation.
OpenStudy (ranga):
Instead of writing x2, I prefer to write it as x^2 (meaning x raised to 2 to indicate that 2 is an exponent).
OpenStudy (anonymous):
36=4*9
OpenStudy (ranga):
You solve for k and got k = 4.
Put just k = 4 in the equation y = k * x^2
y = 4x^2 is the equation we are after.
Which answer choice has y = 4x^2 (also written as y = 4x2)
OpenStudy (anonymous):
oh duh c.:)
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