Please Help I will fan and give medals!!!:) Write the quadratic variation equation for the relationship: y varies directly with x2 and y = 36 when x = 3. A.y = 12x B.y = ¼x2 C.y = 4x2 D.y = x2 + 25 @ranga
"y varies directly with x^2" implies y = k * x^2 ---- (1) When x = 3, y = 36 Plug the values into equation (1) and solve for k.
36=k*9
then I should divide each side bye 9?
Yes. Divide each side by 9 to solve for k.
so 4=k?
yes, k = 4. Put k in the equation y = k * x^2 and see which answer choice represents the equation.
Instead of writing x2, I prefer to write it as x^2 (meaning x raised to 2 to indicate that 2 is an exponent).
36=4*9
You solve for k and got k = 4. Put just k = 4 in the equation y = k * x^2 y = 4x^2 is the equation we are after. Which answer choice has y = 4x^2 (also written as y = 4x2)
oh duh c.:)
Yep! :)
Thanks again!
You are welcome.
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