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Mathematics 18 Online
OpenStudy (anonymous):

@phi i need help with this one too

OpenStudy (anonymous):

OpenStudy (anonymous):

@tHe_FiZiCx99

OpenStudy (phi):

change both numbers into improper fractions This shows you how to do it http://www.khanacademy.org/math/cc-fourth-grade-math/cc-4th-fractions-topic/cc-4th-mixed-numbers/v/changing-a-mixed-number-to-an-improper-fraction

OpenStudy (the_fizicx99):

so 8*6 + 1 and 4*3 + 2 Do the K.S.F Keep the first fraction. Switch the sign from division to multiplication And flip the second fraction 49/6 * 3/14 147/84 How many times does 84 go into 147?

OpenStudy (anonymous):

\[8*6=32+1=33 \] am i along the right path?

OpenStudy (anonymous):

oh

OpenStudy (the_fizicx99):

8*6 isn't 32 >.<

OpenStudy (phi):

yes that is the right idea, but 6*8 is 48

OpenStudy (anonymous):

oh

OpenStudy (the_fizicx99):

We did this earlier ;~; you forgot

OpenStudy (anonymous):

84 does into 147 1 time with a remainder of 63. correct?

OpenStudy (phi):

did you change the two numbers into improper fractions? what did you get ?

OpenStudy (anonymous):

isnt it 147/84........? cuz dats what he said.....

OpenStudy (the_fizicx99):

Yes, it goes in 1 time and 63/84 = 0.75 or 3/4

OpenStudy (phi):

If you are going to do these problems, you may as well learn how to do them. can you change the numbers into improper fractions? you would get 147/84 which simplifies to 1 with a remainder of 63 but it is easier to simplify before you get that far.

OpenStudy (anonymous):

so 1 3/4.....?

OpenStudy (anonymous):

i think i got how to do it now!!!!!!! omg yay!! ty guys soooooooo much omg

OpenStudy (anonymous):

so first change the proper into inporper fractions (multiply the whole number by denominator) and then replace the numerator with the number you got leaving the denominator the same. then multiply the denominators together then the numerators together. next see how many times the denominator and the numerator go into each other correct?

OpenStudy (anonymous):

that makes no sense does it

OpenStudy (phi):

the first step. you multiply the whole number by the denominator THEN ADD the numerator. 2 ⅓ you multiply the whole number 2 times the denominator 3 to get 6. then add the numerator 1 to get 7. the denominator stays 3 and you get 7/3

OpenStudy (phi):

then multiply the denominators together then the numerators together. you do that if you multiply fractions if you divide fractions, you first "FLIP" the fraction and then multiply \[ \frac{1}{2} \div \frac{1}{2} = \frac{1}{2} \cdot \frac{2}{1} \]

OpenStudy (anonymous):

oohhhhhhhhh oki ty ty ty ty again

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