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PLEASEE HELP MEEE!:/ What is the sum of the arithmetic sequence 149,135,121,..., if there are 28 terms? a. -1,204 b.-1,176 c. -1,148 d. -1,120
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keep subtracting 14 i think
i did but then it become negative & gets lower:/ get me?
the ancer is D -1220
answer
yes D i the answer
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S = (n/2) × (2a + (n-1)d) This is the formula s=(28/2)*((2*149)+(28-1)*-14)=-1120
sorry n stands for the number of terms in the sequence, a- first term d- difference
thank you so much!
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