Question

Can someone help me please???
What is the solution to x= squareroot 3x+10?

Answer 1

first square both sides, becoming:\[x^2 = 3x + 10\]
you can complete the square or put it in this form and use the quadratic formula:\[x^2 - 3x - 10 = 0\]

Answer 2

let me know if i should keep going

Answer 3

yes

Answer 4

for polynomial of form: \[ax^2 + bx + c\]you can use the quadratic formula to solve for x.
you will get two answers because of the plus/minus sign (one for plus one for minus)
quadratic formula:\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
we have a = 1, b = -3 and c = -10.
we simply plug them in the quadratic formula:
\[x = \frac{ -(-3) \pm \sqrt{(-3)^2 - 4(1)(-10)} }{ 2(1) } = \frac{ 3 \pm \sqrt{49} }{ 2 } = \frac{ 3 \pm 7 }{ 2 }\]
answers are:\[x = 5\ and\ x = -2\]

let me know if you have

Answer 5

thanks