Question

(-1, 3) and perpendicular to y = -one thirdx + 7

Answer 1

a perpendicular line has a flipped opposite slope.
slope of y = -1/3 x + 7
is -1/3 the flipped of it would be -3 then opposite would be 3
so the line perpendicular to it would have a slope of 3
so given m=3 and a point of (-1, 3)
now do you know how to do it? :)

Answer 2

im doing this test and this test I have no clue about and I try to learn it but I never get it I suck at math :(

Answer 3

no one sucks at math, you just need more practice and proper teaching :)
I'll do my best to help in the ways that I can! :D

Answer 4

y = 3x - 12

y = 3x + 6

y = 3x - 6

y = 3x

Answer 5

your saying the slope is 3 so it would be d?
bc the 1/3 cancel out the 1 out to go to 3

Answer 6

not quite :)
slope = 3
means that in y = mx + b
would become y = 3x + b
then to find b, you can temporarily plug in the given point (-1, 3) as (x, y)
so when you plug in -1 for x and 3 for y
you get 3 = 3(-1) + b
solve for b and tell me what you get :)

Answer 7

b = -6

Answer 8

close! :)
3 = 3(-1) + b
3 = -3 + b then add 3 to both sides
+3 +3
6 = b
so b = 6

Answer 9

then you can plug b into y = 3x + b
and get... y = 3x + 6
tah-dah! :)

Answer 10

can you help me with more ?

Answer 11

sure :)

Answer 12

Choose the equation below that represents the line passing through the point (1, -4) with a slope of one half

Answer 13

there a lot more :(

Answer 14

it the same but with the one half

Answer 15

slope = m = 1/2
so for y = mx + b
turns into y = 1/2 x + b
then you can temporarily plug in the point (1, -4)
which mean plug in 1 for x and -4 for y
so solve for b when given (-4) = 1/2 (1) + b

Answer 16

1

Answer 17

no that wrong

Answer 18

try again then :)

Answer 19

(hint: add 1/2 to both sides)

Answer 20

so 1/2

Answer 21

bc it cancel it out right

Answer 22

(-4) = 1/2 (1) + b
-4 = 1/2 + b then subtract 1/2 from both sides
-1/2 -1/2
-4 1/2 = b
so b = - 4 1/2 or -4.5 or -9/2

Answer 23

which you would then plug into y = 1/2 x + b
so y = 1/2 x - 4 1/2

Answer 24

y - 4 = one half(x - 1)

y + 4 = 2(x - 1)

y + 4 = one half(x - 1)

y - 4 = 2(x + 1)

but there 4 with all the answers

Answer 25

ooooohhhhhhhhh
point slope form: y - y1 = m(x - x1)
when m = slope and given the point (x1, y1)

Answer 26

so plug in m = 1/2
x1 = 1 and y1 = -4
into y - y1 = m(x - x1)

Answer 27

no canceling out involved, but plug in :)

Answer 28

what

Answer 29

im an little lost

Answer 30

1,1 1,4 ?

Answer 31

y - y1 = m (x - x1) is the point-slope form for a line, plug in what they gave you
(-4) (1/2) (1)

Answer 32

y - 4 = one half(x - 1)

Answer 33

close! remember that -(-) = +
so -(-4) = +4

Answer 34

so y + 4 = one half(x - 1)

Answer 35

so would the y - be an +

Answer 36

yep! :)

Answer 37

so c y + 4 = one half(x - 1)

Answer 38

correct! :)

Answer 39

:) I have 7 left I been doing some while waiting

Answer 40

would you care to help me again

Answer 41

sure :) although I have about 20 minutes until my bed time :P

Answer 42

:/ alright I will look for the hardest one

Answer 43

alright all where hard so I just went to the next one /Choose the equation of the line passing through the point (-2, 6) and parallel to y = one halfx - 8.

Answer 44

parallel means that they have equal slope
y = one halfx - 8
^ 1/2 is the slope
so the new line has a slope of 1/2
so so far we have y = 1/2 x + b

Answer 45

y = 1/2 x + b alright

Answer 46

then temporarily plug in point (-2, 6)
so given 6 = (-2)(1/2) + b
solve for b

Answer 47

y = one halfx + 5

Answer 48

close :)
6 = (-2)(1/2) + b
6 = -1 + b so add 1 to both sides
so b = 7

Answer 49

take off the 5 put on 7

Answer 50

yep :)

Answer 51

see, you're starting to get it now! :D

Answer 52

I guess it time of bed right and yea but last year I fail badly I had an 7% but I try and try and I just really bad am in geometry now and have an b+ but I have to remake this up so I want to learn right not just be stupid and give up in high school

Answer 53

it's alright :) I'm failing math too :P
if you ever need help when I'm not around,
you can tag people by putting a "@" in front of their username
some people that can help are
ehuman
inkyvoyd
esshotwired
nikato
RadEn
ranga
shamil98
SolomonZelman

Answer 54

:) thank you well I hope you have an amazing night while I get more help :P

Answer 55

glad I could help :) good night

Answer 56

good night