Can someone help me on a last question!? Please Ill give a medal. "Prove that a line parallel to one side of a triangle divides the other two sides proportionally. Be sure to create and name the appropriate geometric figures. "

Question

ganeshie8 · Answer

draw it out

anonymous · Answer

I dont know how and the picture didn't came with the question.

ganeshie8 · Answer

its okay, lets draw a rough picture :)
just a triangle and a line parallel to one of its sides

anonymous · Answer

:)

ganeshie8 · Answer

u got some clue ? or still need some assistance ha ? :)

anonymous · Answer

I feel if you do the shape like this i would understand it more. because i know the geometric figure |dw:1389340751141:dw|

ganeshie8 · Answer

that works too :) lets stick to ur diagram

anonymous · Answer

Ok great :)

ganeshie8 · Answer

1. $\angle D \cong \angle A$               1.  Corresponding angles
2.  $\angle B \cong \angle B$               2. By reflexive property
3. $\triangle ABC \sim \triangle DBE$     3. By AA similarity

ganeshie8 · Answer

half part of the proof is done.
see if you can digest above...

ganeshie8 · Answer

we have just proved that both triangles are similar; next we will take ratios and conclude the proof

anonymous · Answer

AD/AB = BE/BC

anonymous · Answer

I have a feeling I did this wrong?

ganeshie8 · Answer

yes slightly wrong. u need to honor the sides-belonging-to-respective-triangles

ganeshie8 · Answer

wat that means is simply this :-
sides belonging to same triangle must be on TOP  or BOTTOM.

ganeshie8 · Answer

AD/AB = BE/BC 

this is wrong cuz, AD and BE are on top, but they dont belong to same triangle!

anonymous · Answer

So AB and BC are suppose to be on top.

ganeshie8 · Answer

Yes !

ganeshie8 · Answer

you got it ! write the correct proportion now :)

anonymous · Answer

AB/AD = BC/BE

anonymous · Answer

Like this?

ganeshie8 · Answer

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