Question

Select the system of linear inequalities whose solution is graphed.





system of linear equations



A.


y < 3x – 2, x + 2y > 4


B.


y > 3x – 2, x + 2y < 4


C.


y ≥ 3x – 2, x + 2y ≤ 4


D.


y ≤ 3x – 2, x + 2y ≥ 4

Answer 1

http://static.k12.com/calms_media/media/1317000_1317500/1317436/1/3b12f85214e56527f39cff765d3a804da8e13f08/HS_A1G2_S1_08_07_ART3.jpg

Answer 2

@twinz1999 @imawesome101

Answer 3

@Taylor<3sRin @tester97 @Dakota005 @darkshadowcj @Dakotafox79

Answer 4

@SkyDoesMinecraft

Answer 5

@random231

Answer 6

@randomaccesmemory

Answer 7

help asap plz

Answer 8

hav any idea?
where's ur problem?

Answer 9

the top

Answer 10

This is Algebra 1 correct?

Answer 11

i think yea

Answer 12

Hold on, let me look in my notes to see if I have anything on this.. I know I got things on Linear Systems of Equations.. Which seems to be similar, but idk about the graphing.. Let me check though :)

Answer 13

ok great!!!!!!!!!!!!!!!!!!!

Answer 14

It tells me mostly about solving inequalities.. But nothing about graphs.. What grade are you in?

Answer 15

8th but im 15 failed a few grades

Answer 16

Hmm, That's fine. I'm in 10th.. Hah. Found something that may help..

let's follow those steps to graph x + y ≤ 3.

Step 1. Graph the Boundary Line

To graph the boundary line, substitute the = sign for the ≤ sign to get x + y = 3, and use the x- and y-intercepts to graph the line.

Because the value of y on the x-intercept is 0, we get x + 0 = 3, which means x = 3, and the x-intercept is (3, 0).

In the graph, the boundary line is represented by a solid line because the inequality in the original equation is ≤. Observe that the boundary line divides the graph into half planes.




Step 2. Plug in a Test Point That Is Not on the Boundary Line

A simple test point is (0, 0).

Step 3. Shade the Solutions

x + y ≤ 3
0 + 0 ≤ 3
0 ≤ 3 (true)

Because the test point (0, 0) is a solution, shade the region that contains the test point.

We now know that x + y ≤ 3 can be represented by the graph shown here.


I have attached the graph that it's talking about shaded wise..

Answer 17

Does that help you understand? :)

Answer 18

my graph is http://static.k12.com/calms_media/media/1317000_1317500/1317436/1/3b12f85214e56527f39cff765d3a804da8e13f08/HS_A1G2_S1_08_07_ART3.jpg

Answer 19

I know, I was giving an example, to see if you could maybe solve it on your own with the information I provided.

Answer 20

ok

Answer 21

so c right

Answer 22

@darkshadowcj

Answer 23

I would believe that's what it is.. But get a seconds opinion to make sure.. Wouldn't want you to get it wrong if I'm wrong =/.

@dominick6541 @robtobey

Answer 24

hes a friend i was wonderin if he was here