If cosx= 0.8, and 0
I know that x is in the first quadrant, but need more guidance.
You know the value of cos(x). Now find sin(x). Because 2sin(x)cos(x) = sin(2x), you now know what the value of sin(2x) would be. From that, figure out cos(2x). Then use tan(2x) = sin(2x)/cos(2x) I hope I made sense.
Note that sin(x) = sqrt(1 - cos^2(x)) so you can find the value of the other one.
kk, I said guidance not work, thank you for the help.
I know from here I think.
OR 0.8 = 4/5 = cos(x). This seems like a 3-4-5 triangle.
No problem haha! I totally wrecked the previous question.
No, I am actually pretty stupid. i keep trying to do this but come back to co(x)=0.8 every time, dky.
|dw:1389379726248:dw|
Join our real-time social learning platform and learn together with your friends!