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The square root of the quantity 72 times n to the thirteenth power.
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I have no clue how to do this.
I'm not sure if I get it.. sqrt(72n)^13 ?
Yes, that's it
or sqrt(72)(n)^13
The first one.
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[sqrt(x)]^13 = x^6.5 = x^6 sqrt(x)
Here are the answer choices : A. 8n square root 3n^6 B. 3n^6 square root 8n C. 8n^6 square root 3n D. 6n^6 square root 2n
I have like 10 of these do do =(
right, I'm trying to solve it, you have to use the proporties of exponents http://www.mathplanet.com/education/algebra-1/exponents-and-exponential-functions/properties-of-exponents
@satellite73 can you help here?
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sqrt (72n^13) find factors of 72 and n that will give perfect sq rewrite sqrt (9 X 4 X 2 X n^12 X n^1) 3 X 2 X n^6 X sqrt2n
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