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Chemistry 16 Online
OpenStudy (anonymous):

draw the structrual formula for a)ethylcyclopentene b)5-ethyl-2,2-dimethyl-3-heptene c)3,4-dimethylhexyne

OpenStudy (wolfe8):

This should help: http://www.chemguide.co.uk/basicorg/conventions/names.html When doing the reverse you should start from the back of the name. Can you do that?

OpenStudy (anonymous):

what i get for a) is a hexagon with ch2 and ch3 connected at first spot

OpenStudy (anonymous):

or ch5

OpenStudy (wolfe8):

Ok first you know it's 5 carbons in the main ring. Then since there is no number stating where the ethyl is, it is understood that it is at the first carbon. Do you know what an ethyl is?

OpenStudy (anonymous):

2nd one I'm not sure if i'm right or wrong |dw:1389464914102:dw|

OpenStudy (anonymous):

Ethyl is CH2CH3 or CH5 right?

OpenStudy (anonymous):

and c) I got |dw:1389465207361:dw|

OpenStudy (anonymous):

also what is |dw:1389465306632:dw|

OpenStudy (anonymous):

always remember that when your given a compound with -yne, it MUST contain a triple bond, -ene contains double bond and -ane contains single bond.

OpenStudy (wolfe8):

Ethyl is C2H5 derived from ethane C2H6 according to http://en.wikipedia.org/wiki/Ethyl_group Sorry I forgot myself. I THINK the second one looks right, except the ethyl.

OpenStudy (anonymous):

so the last drawing will be 4,4-dimethylpent-2-ene.........also, always remember that the double bond has priority.

OpenStudy (anonymous):

so for the second i should write C2H5 instead of CH2CH3?

OpenStudy (anonymous):

if triple bond it should be 4,4-dimethylpentyne right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you could write C2H5 as its much clear.

OpenStudy (anonymous):

for the b) should I of taken out the H's from the double bond? It should just be c's or ch's?

OpenStudy (anonymous):

|dw:1389469791478:dw|

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