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What is the single logarithm of 5(logbM + logbN) - 2 logbC ?
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\[5(\log _{M} + \log _{N}N) - 2 \log _{b}C \]
they are different, which one is correct one?
Sorry, its, \[5(log _{b}M+log _{b}N)−2log _{b}C\]
\(log _{b}M+log _{b}N=log_{b}MN\) ok?
Yea
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where does the 5 go?
So \(5(log _{b}M+log _{b}N)= log_{b}(MN)^5 =log_{b}M^5N^5\) ok?
and \(2log_{b}C=log_{b}C^2 \) ok?
\[log_{b}M^5N^5-log_{b}C^2=log_{b}{\frac{M^5N^5}{C^2}}\]
|dw:1389476149678:dw|
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