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Mathematics 18 Online
OpenStudy (anonymous):

Stats helps.

OpenStudy (anonymous):

Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score 0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots).

OpenStudy (anonymous):

Assuming that the probability for each shot is independent, what number of points is Jenny most likely to make?

OpenStudy (anonymous):

nevermind you guys, i got! thank you for stopping by though. i was told all had to do was the tree chart thingy and multiply the possbilites. idk if that makes sense, but i got it.

OpenStudy (anonymous):

what's the answer? i'd like to know

OpenStudy (anonymous):

1

OpenStudy (anonymous):

it's kinda obvious anyways, because its 60%

OpenStudy (anonymous):

I thought it was 0.96? Is this an expected value problem?

OpenStudy (anonymous):

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