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Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score 0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots).
Assuming that the probability for each shot is independent, what number of points is Jenny most likely to make?
nevermind you guys, i got! thank you for stopping by though. i was told all had to do was the tree chart thingy and multiply the possbilites. idk if that makes sense, but i got it.
what's the answer? i'd like to know
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it's kinda obvious anyways, because its 60%
I thought it was 0.96? Is this an expected value problem?
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