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OpenStudy (anonymous):
In a class, 6 students are divided into 3 groups of 2 students each. In how many ways can the 3 groups be formed?
@Zarkon @digitalmonk
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OpenStudy (anonymous):
First chose 2 from 6, then 2 from 4, then 2 from 2.
OpenStudy (anonymous):
6C2+4C2+2C2?
OpenStudy (anonymous):
add or multiply?
OpenStudy (anonymous):
Well, you'd do it in sequence.
OpenStudy (anonymous):
sequence tasks are multiplied.
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OpenStudy (anonymous):
90 ways?
OpenStudy (anonymous):
90 looks right.
OpenStudy (anonymous):
multiplication is all items can or cannot be repeated ??
OpenStudy (anonymous):
Multiplication just how you combine two sequential tasks. It has nothing to do with repetition.
OpenStudy (anonymous):
ohh..
understand now
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OpenStudy (anonymous):
Choosing does not allow repetition and order is not considered.
OpenStudy (anonymous):
That ensures each group is counted once, rather than twice for each permutation of the two person group.
OpenStudy (anonymous):
We did not do any counting which would factor in the order of the groups either, meaning we treated groups as being indistinct.
OpenStudy (anonymous):
ohh, you make me concepts cleared. thanks a lot
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