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A cup falls off of a table from a height of 0.75 m. What is the impact speed of the cup? A. 5.15 m/s B. 10.2 m/s C. 3.83 m/s D. 14.7 m/s
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is the equation v = u + at @MayankD
no not this time since the displacement is given as opposed to time of free fall
are you familiar with the work energy theorem?
doesn't it cause the objects speed to change? @MayankD
Or we can use the equation v^2=u^2 + 2as V->final velocity u_.initial velocity S->displacement a->acceleration
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so njust substitute initial velocity as 0 and s as 0.75 and a as 9.8m/s^2
just*
=0^2+2(9.8) is what i have so far. what would the displacemnet be? .75? @MayankD
yes
0^2+2(9.8)(.75) =14.7 correct? @MayankD
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