Ask your own question, for FREE!
Physics 24 Online
OpenStudy (anonymous):

A cup falls off of a table from a height of 0.75 m. What is the impact speed of the cup? A. 5.15 m/s B. 10.2 m/s C. 3.83 m/s D. 14.7 m/s

OpenStudy (anonymous):

is the equation v = u + at @MayankD

OpenStudy (anonymous):

no not this time since the displacement is given as opposed to time of free fall

OpenStudy (anonymous):

are you familiar with the work energy theorem?

OpenStudy (anonymous):

doesn't it cause the objects speed to change? @MayankD

OpenStudy (anonymous):

Or we can use the equation v^2=u^2 + 2as V->final velocity u_.initial velocity S->displacement a->acceleration

OpenStudy (anonymous):

so njust substitute initial velocity as 0 and s as 0.75 and a as 9.8m/s^2

OpenStudy (anonymous):

just*

OpenStudy (anonymous):

=0^2+2(9.8) is what i have so far. what would the displacemnet be? .75? @MayankD

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

0^2+2(9.8)(.75) =14.7 correct? @MayankD

OpenStudy (anonymous):

Yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!