Distance-Time Graph Question! (MEDAL) A motorist left town X at 08 00 for town Y, situated 120 km away, travelling at a constant speed v km/h, so as to arrive at Y at 10 40. But after travelling for 80 minutes, his car developed engine trouble and he had to stop for 30 minutes to repair it. Then he continued his journey at a speed of u km/h, so as to arrive at Y ar 10 40. (a) Sketch the distance-time graph of the car. (I DID THAT ALREADY) [attached] (b) Calculate the values of v and u. (found "v" but had trouble with "u". plz explain how to find both again)
is the answer of speed u ..is 50km/h ??
I know both the answers. Don't know how!
firstly the value of v would be 45km/h ryt .?
YEA
That was easy! But can't find u
he travelled for 80 minutes...with speed v...that means he travelled \[\frac{ 4v }{ 3 }km\]
which is by putting the value as 45 ...we get ...60 km ..!
that means after 60km his car got trouble ...he waited 1/2 an hour ..! then started.
no no ..~! why 59 /...60 only ..?
Oh yea, it's 60 km...
actual journey will take 8/3 hours ...but he wasted ..110 minutes ..till now which is 11/3 hourse ..
that means ..now he has to reach his destination ...in 5/6 hours ...right .?\[\frac{ 8 }{ 3}-\frac{ 11 }{ 6 } =\frac{ 5 }{ 6 }\]
so remaining 60 km must be covered in 5/6 hours ...so the speed u must be 60 divided by 5/6 which is ..72km/h ...sorry ...i was wrong in the beginning ..but u=72
OmG! That's the right answer! But u did that using calculations. How to find this value using the graph?
How do I find the speed using this information? Motorist starts journey at = 09 50 Motorist Journey ends at = 1040 Journey Distance = 60 km
umm ...an attempt ..try using the slope concepts.?
Well, I am doing the "Kinematics" so it's about Graphs... What do I do first? Speed = Distance/Time Speed = 60/Time How to find time?
1040 - 0950?
some how u need to get time as 5/6 hours ..which is 50 minutes ...
yes u were right ..
The time between 0950 and 1040 is 50 mins?
yes ..so u are der ..u have done that !
How do I find time using this Graph?
Oh wait! I found the time! WTF
Hmm dunno how but did somehow! Thanks!
apply slope as y2-y1/x2-x1
my medal ....???
gave it already...
U didn't got?
lol ..thank u
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