Question

area enclosed by y= root(1+x^3) , y=.5x+2, y=0

Answer 1

Could someone set up the integral part?

Answer 2

well you'll need to find the points of intersection of the curves...

Answer 3

the upper graph is linear

so its

\[\int\limits_{0}^{a} (0.5x + 2) dx - \int\limits_{0}^{a} (\sqrt{1 + x^3}) dx\]

where (a, f(a)) is the point of interesction of the 2 curves

Answer 4

I have the integral from -4 to 2, but when I plug it into the calculator it does not want to calculate.

Answer 5

so you need to use

\[\int\limits_{-4}^{2}(0.5x + 2)dx - \int\limits_{-1}^{2}(\sqrt{1 + x^3}) dx\]

because the domain of the 2nd function is restricted to x >= -1