Question

1. Solve the system of equations below algebraically.

2x + 3y = 6
-5x + 2y = 4

Answer 1

2)
5y + 3x = -10
\[-\frac{ 5 }{ 3 }y = x - \frac{ 4 }{ 3 }\]

Answer 2

You need to solve for x as it relates to y in one of the equations. Then plug that value into the second equation. Thus if 2x + 3y= 6, then 2x = -3y +6 or x= -3/2y +3. Take this and plug it into the second equation to solve for y.
-5 (-3/2y +3) +2y =4. Once you solve for y you can get x.

Answer 3

2x + 3y = 6
-5x + 2y = 4

10x + 15y = 30
-10x + 4y = 8
_________________
0x +19y = 38
y = 2

2x + 3 (2) = 6
2x = 6 -6
x = 0