1. Solve the system of equations below algebraically.

2x + 3y = 6
-5x + 2y = 4

Question

1. Solve the system of equations below algebraically.

  2x + 3y = 6
-5x + 2y = 4

anonymous · Answer

2) 
5y + 3x = -10
$$-\frac{ 5 }{ 3 }y = x - \frac{ 4 }{ 3 }$$

anonymous · Answer

You need to solve for x as it relates to y in one of the equations.  Then plug that value into the second equation.  Thus if 2x + 3y= 6, then 2x =  -3y +6 or x= -3/2y +3. Take this and plug it into the second equation to solve for y. 
-5 (-3/2y +3) +2y =4. Once you solve for y you can get x.

anonymous · Answer

2x + 3y = 6 
-5x + 2y = 4

10x + 15y = 30
-10x + 4y = 8
_________________
0x +19y = 38
y = 2

2x + 3 (2) =  6
2x = 6 -6
x = 0