Mathematics
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OpenStudy (anonymous):
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -12 and 768, respectively
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OpenStudy (nikato):
So now u know the geometric sequence formula?
OpenStudy (nikato):
Well it's
an= a(r) ^ n-1
Where a=1st term
R=ratio
N= number of terms
OpenStudy (anonymous):
@nikato i get that but how do i do it if i dont have the first term
OpenStudy (nikato):
Ok, u want to solve though system of equations.
Did u plug everything it so u have to different equations?
OpenStudy (anonymous):
im honestly so confused
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OpenStudy (nikato):
Ok, so just follow along
OpenStudy (anonymous):
Thank you so much~
OpenStudy (nikato):
Plug in the numbers into the geometric formula
768=ar^4
-12=ar^1
Ok with this?
OpenStudy (anonymous):
Where did you get the ^4 from?
OpenStudy (nikato):
So in the geoetric formula it's n-1. Since its the 5th term, it's 5-1 or 4
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OpenStudy (anonymous):
oh okay okay
OpenStudy (anonymous):
@nikato
OpenStudy (nikato):
So now I'm gonna divide both equations
OpenStudy (nikato):
768=ar^4
------------
-12=ar^1
OpenStudy (anonymous):
divided them by eachother
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OpenStudy (nikato):
Remember a/a=1 and ur just subtracting exponents when u divide
So this equals
-64=r^3
Can u find r?
OpenStudy (nikato):
And yes, I divided them by each other
OpenStudy (anonymous):
no :/
OpenStudy (nikato):
So u want to cube root both sides. Which u can do on ur calculator
OpenStudy (anonymous):
-4
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OpenStudy (nikato):
Or u can factor 64 which is 4x4x4 but becuz it's negative it's -4x-4x-4
OpenStudy (nikato):
Ok. Yes. So our r=-4
OpenStudy (anonymous):
how do we find a?
OpenStudy (nikato):
So now let's plug it back into one of the original equation. Lets use the second one
-12=ar^1
So
-12=a(-4)^1
-12=a(-4)
So now, can u find a?
OpenStudy (anonymous):
i got -3/4
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OpenStudy (anonymous):
wait no
OpenStudy (anonymous):
3
OpenStudy (anonymous):
would it be an=3*-4^n-1
OpenStudy (nikato):
Yea, correct. Great job!
OpenStudy (anonymous):
Thank you so much i actually get it now!
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OpenStudy (nikato):
Ur welcome!