How do you graph triangle ABC with the following points?: A(0, 0), B (2, 4), C (-6,3)
0,0 is the point of origin or where x and y intersect at 0.
Just plot the points and connect the dots.
|dw:1389571893324:dw|
But that's a straight line?
try using this -> ttp://pequotwar.org/wp-content/uploads/2013/05/2D_Cartesian_Coordinates.png to plot it
Your plot for -6, 3 is incorrect.
\(\bf \begin{array}{rclllll} &x&y\\ \hline\\ &({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\\ &({\color{red}{ 2}}\quad ,&{\color{blue}{ 4}})\\ &({\color{red}{ -6}}\quad ,&{\color{blue}{ 3}}) \end{array}\)
"Graph triangle ABC. Contruct the medians for the triangle using a compass and a straightedge"
http://www.mathsisfun.com/geometry/construct-linebisect.html <-- click on Play button
median -> bisector -> line that cuts it in half
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