Question

Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry.

Its solving a quadratic equation that had complex numbers

Answer 1

\[2x^2-ix-2+i=0\]

Answer 2

:/ Sorry... I can't help..

Answer 3

:'(

Answer 4

@jdoe0001

Answer 5

tried using the quadratic formula yet?

Answer 6

Phew! GO JDOE!

Answer 7

I tried it, i solved it but i got the wrong answers. I tried it over and over again. I looked up videos, still wrong answer

Answer 8

\(\large \begin{array}{llll}
{\color{red}{ 2}}x^2&{\color{blue}{ -i}}x&{\color{green}{ -2+i}}=0\\
\uparrow &\ \uparrow &\quad \uparrow \\
{\color{red}{ a}}&\ {\color{blue}{ b}}&\quad {\color{green}{ c}}
\end{array}\\ \quad \\ \bf
x=\cfrac{i\pm\sqrt{i^2-4(2)(-2+i)}}{2(2)}\implies x=\cfrac{i\pm\sqrt{-1-8(-2+i)}}{2(2)}\\ \quad \\
x=\cfrac{i\pm\sqrt{-1+16-8i}}{2(2)}\implies x=\cfrac{i\pm\sqrt{15-8i}}{4}\)

Answer 9

ok..got that

Answer 10

well.. that's.... as far as I can see it going...

what does your answer say?

Answer 11

x=1 and x=-1+0.5i

Answer 12

hmmm I don't see it simplifying ... to that

Answer 13

:(