Question

Find the vertex of the graph of the function.

f(x) = (x - 5)2 + 10

I know you use f(x) = a(x-h)^2 + k but how?

Answer 1

\(\bf f(x) = (x - {\color{red}{ 5}})2 + {\color{red}{ 10}} \implies f(x) = a(x-{\color{red}{ h}})^2+{\color{red}{ k}}\qquad vertex\quad ({\color{red}{ h,k}})\)

Answer 2

So it would be (-5,10)

Answer 3

well, the - or the + aren't part of it, so (5, 10)

if you had say \(\bf (x+5)^2-10\implies (x-(-5))^2+(-10)\qquad vertex\implies (-5,-10)\)

Answer 4

so... the - in the parentheses, and the + outside, are just part of the TEMPLATE
no the sign of the value