Question

PLEASE HELP!!!!!

The sum of two consecutive even integers is 234. What is the larger integer?

114

116

118

124

Answer 1

x + (x+2) = 234
2x + 2 = 234
2x = 232
x = 116 .
so the larger integer is 118

Answer 2

You will have to find a way to describe these numbers.
To do so, first think how you can describe an even number:
You could call it 2a, because it is even, so you can divide it by 2. This means 2 is a factor, so the number is 2*another number, or 2a.

Now the next even number is 2 more than 2a, so it is 2a+2.

We can change the whole story into an equation now:

2a(2a+2)=118.

If you solve it, you have got a.
Then the larger number is 2a+2.

Will you try this now?

Answer 3

Thank you @perl :)

Answer 4

Ok. So the answer is 118?

Answer 5

@perl: it would be better to leave something to do for RosieF, instead of just giving the complete answer IMO.

Answer 6

Then there is the typo in my reply: 2a + 2a+2 = 234. This now has to be solved.

Answer 7

Thank you 2 @ZeHanz :) I'd give u a medal 2 if I could ;)

Answer 8

@ZeHanz
it is not necessary to write it the integer as 2a

Answer 9

my method is straightforward, it works for even and odd integer consecutive problems

Answer 10

@perl I know, the numbers being even is irrelevant. But only afterwards that becomes clear.