Question

Name additional roots of 1-i and 5

Answer 1

http://en.wikipedia.org/wiki/Complex_conjugate_root_theorem

Answer 2

could you please simplify it, it sounds like jargon on the Wikipedia page.

Answer 3

fair.... ahemm anyhow.. .in a quadratic equation, if you end up with a complex root, that means, it doesn't come alolne by herself, it has a "conjugate" companion

Answer 4

so it would have 1+i?

Answer 5

yes \(\bf x= \cfrac{ - b \pm {\color{red}{ \sqrt { b^2 -4ac}}}}{2a}\implies x= \cfrac{ - b \pm {\color{red}{ i}}}{2a}\)

so as you can see, the root in the quadratic formula, will spit out 2, not 1, 2 complex, two complex conjugates

Answer 6

I see now but...

Answer 7

I get it now
Thanks so much !

Answer 8

yw