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What is the slope of a horizontal line?
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try taking any 2 points on any horizontal line, and plugging them into the slope formula. (the y-values will always be the same)
dy/dx = (y2-y1)/(x2-x1) etc.
why are you differentiating?
the slope is the change in y divided by the change in x, the tangent, the differential, etc. If I wrote the equation with an editor, dy would have been capital delta y....
I know, but jr221 hasn't learned this yet.
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Yes, the point was the right-hand-side of the equation, not the "dy/dx."
But I agree that "dy/dx" was a poor choice.
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