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Mathematics 21 Online
OpenStudy (anonymous):

Sigma Notation HELP!!!

OpenStudy (anonymous):

\[\sum_{n=1}^{12}2n+5\] a. 29 b. 36 c. 216 d. 432

OpenStudy (anonymous):

\[\sum_{n=2}^{10}-2n-3\] a. −270 b. −135 c. 135 d. 270

OpenStudy (anonymous):

Let's look at this. The sigma is telling us that n =1, n=2, n=3 . . . n=12 2(1) + 5, 2(2) + 5) . . . 2(12) + 5 Are you with me so far?

OpenStudy (anonymous):

\[\sum_{n=3}^{12}20(0.5)^{n-1}\] a. 9.99 b. 19.95 c. 29.98 d. 39.96

OpenStudy (anonymous):

\[\sum_{n=1}^{5}3(-2)^{n-1}\] a. −93 b. −33 c. 33 d. 93

OpenStudy (anonymous):

If you could also explain how to do it so I can do it on my own in the future that would be great. The lesson did a poor job of explaining it so I don't understand it at all. Thanks. Medal for best answer.

OpenStudy (anonymous):

@kirbylegs No, I don't:/ Sorry, I don't get sigma notations at all. Like, what do the numbers on top and bottom mean?

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