Can you tell me how to do it? Don't give me answers...I want to know how to solve it... What is the value of x in the proportion (x-1)/5 = (4x + 2)/35?
\[\frac{ (x-1) }{5}=\frac{ 4x+2 }{ 35 }\]
cross multiply the top up
What do you mean?
\(\bf \cfrac{x-1}{5}=\cfrac{4x+2}{35}\quad \textit{times 35 each side}\\ \quad \\ {\color{red}{ \cancel{35}}}\cdot \cfrac{x-1}{\cancel{5}}={\color{red}{ \cancel{35}}}\cdot \cfrac{4x+2}{\cancel{35}} \implies {\color{red}{ 7}}\cdot (x-1)={\color{red}{ 1}}\cdot 4x+2\\ \quad \\\implies 7x-7=4x+2\)
Ok i see but where did you get 7?
7(x-1) <--- distribution
hmm you meant the .... I see the 7 itself... hm ok
ok i get it! so next 3x = 9? then you divided by 3 and i got 3.
so the answer is 3?
\(\bf \cfrac{x-1}{5}=\cfrac{4x+2}{35}\quad \textit{times 35 each side}\\ \quad \\ {\color{red}{ 35}}\cdot \cfrac{x-1}{5}={\color{red}{ 35}}\cdot \cfrac{4x+2}{35}\implies \cancel{\cfrac{{\color{red}{ 35}}}{5}}(x-1)=\cancel{\cfrac{{\color{red}{ 35}}}{35}}(4x+2)\)
yeah i got that :)
"so the answer is 3?" \(\checkmark\)
Thanks! i understand now! can you help me another question? and i'll try solve it and you check it?
ok
What is the value of x in the proportion x+1/x+3 = 15/21?
\[\frac{ x+1 }{ x+3 }=\frac{ 15 }{ 21 }\]
Is it same as you solve it? or different?
|dw:1389731685759:dw| is that correct so far?
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