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tan theta=12/5, sin theta <0 how would i find the rest of the trig values?
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Are you aware that tan(theta) = sin(theta)/cos(theta)?
yes i am
i understand that the top part of sin is 12, but when i checked in the back up the book the answer was sin= -12/13 and i don't understand how the -13 came into play. I know it has to do with a^2+b^2=c^2 with 5^2+12^2=13^2 but i don't fully understand it.
Hey, I am back
It is given that sin(theta) is negative and tan(theta) is positive. Because tan = sin/cos, it is clear that cos(theta) is also negative.
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The sides of a triangle can be negative as well. The concept me may be confusing, but yeah. Have you heard of the unit circle?
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