Determine the domain of the function. f(x) = 4/(x^2)
I think it's all real numbers except 0 but I'm not sure
correct :)
Could you help me with another?
Sure
domain of: \[f(x)=\sqrt{7+x}\]
Do you have an idea what it might be?
I don't remember how to solve the ones with square roots
Okay, so for what numbers does a square root produce real answer?
I'm not sure...
@Lyrae
Well, it's all real numbres grater then or eqal to 0 (try squaring a negative number on your calculator and you'll get an error or weird answer)
okay
So this gives us that what's inside that root has to be >= 0 This results in the following inequality: 7 + x >= 0
Where x is all real numbres
Do you know the final answer?
So the domain is all real numbers?
If you solve the inequality you get x >= -7 x is all real numbers, so the answer is: all numbres grater than or equal to -7 or in a more formal way \[\left\{x \in \mathbb{R} : x \ge -7\right\}\]
Thank you sosossosososo much!!!!
all real numbres* NP happy to help :)
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