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The proof by indirect method is shown below. In which step does the contradiction appear? Given: –→BD is not ⊥ ↔AC Prove: m∠1 ≠ m∠2 Step 1: Assume m∠1 = m∠2 Step 2: ∠1 and ∠2 are linear pairs and supplementary angles Step 3: ∠1 and ∠2 are right angles Step 4: –→BD ⊥ ↔AC Step 5: m∠1 ≠ m∠2 Step 1 Step 5 Step 2 Step 4
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Look at step 1 vs step 5
Step 4.
Yes. I suppose it does appear at 4 before 5.
hmmm
We were given that they are not perpendicular and yet our assumption implies otherwise
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u think 4 is the best answer
I would say so. However, the contradiction is more obvious in 5 than 4.
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