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MIT 8.01 Physics I Classical Mechanics, Fall 1999 16 Online
OpenStudy (anonymous):

gravel is falling on a conveyor belt at the rate of 12kg per second , the extra power required to move the belt with a velocity of 5m/s is???

OpenStudy (vincent-lyon.fr):

Do you have any idea?

OpenStudy (anonymous):

yes, i do

OpenStudy (anonymous):

power is work divided by time...the time is essentially one second, the Force is 12kg and the distance is 5 meters..therefore, the power is 60 joules a second

OpenStudy (vincent-lyon.fr):

Well, 12 kg is not a force, but knowing the mass and the velocity will allow you to find some new quantity.

OpenStudy (anonymous):

yah i kno it isn't but Force is mass multiplied by acceleration and since acceleration is per second, it still is 12

OpenStudy (anonymous):

and besides what do you mean by new quantity? like momentum?

OpenStudy (anonymous):

oops actually the FORCE is 60 so it would take 300 joules a second

OpenStudy (anonymous):

wait what's the distance then? it didn't state in the question

OpenStudy (anonymous):

wait, it's 5 meters

OpenStudy (anonymous):

so the answer is 300 JOULES A SECOND

OpenStudy (vincent-lyon.fr):

Yes, 300 watts is correct.

OpenStudy (anonymous):

just so u know, I'm actually Will-i-am so YAY i got it right! wait..if u knew that was the right answer why did n't you just say that in the beginning?

OpenStudy (anonymous):

i am just 12 by the way

OpenStudy (anonymous):

i feel like a boss for solving that problem

OpenStudy (anonymous):

yup, a boss

OpenStudy (vincent-lyon.fr):

Well, If you are a boss, can you compute the rate of increase in kinetic energy produced a explain the paradox that arises ? ;-)

OpenStudy (anonymous):

From earth, this is fine because neither speed exceeds c, but if you take the ... although all the clocks in a given inertial frame will run at the same rate. ... appropriate to change delta t and delta x to a different frame, you would find .... The equivalent Newtonian equation for the kinetic energy (energy of motion) is E = 1/2 m v2.

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