Question

need help on a hard problem.. can anyone give me some help..?

Answer 1

\[-x + 5y = 14; (-5,-2) \] Write the equation of a line that is perpendicular to the given line and that passes through the given point.

Answer 2

A. y= 5x - 27
B. y= -1/5x - 27
C. y= -1/5 x - 15 \
D. y= -5x - 27

Answer 3

first write the equation in slope intercept form
5y = x + 14
y = (1/5) x + 14/5

what is the slope of this line?

Answer 4

the slope of this line is damn idk... :(

Answer 5

its the coefficinet of x
slope = 1/5

the general form of the line is y = mx + c where m = slope and c = intercept on y-axis

Answer 6

now the slope of a line perpendicular to this line = - 1 / m

so for our line the slope is - 1 / (1/5)
can you work that out?

Answer 7

umm honestly not really?? ...