need help on a hard problem.. can anyone give me some help..?

Question

anonymous · Answer

$$-x + 5y = 14; (-5,-2) $$ Write the equation of a line that is perpendicular to the given line and that passes through the given point.

anonymous · Answer

A. y= 5x - 27
B. y= -1/5x - 27 
C. y= -1/5 x - 15 \
D. y= -5x - 27

cwrw238 · Answer

first write the equation in slope intercept form
5y = x + 14
y = (1/5) x + 14/5

what is the slope of this line?

anonymous · Answer

the slope of this line is damn idk... :(

cwrw238 · Answer

its the coefficinet of  x  
slope = 1/5

the general form of the line is  y = mx + c  where m = slope and c = intercept on y-axis

cwrw238 · Answer

now the slope of a line perpendicular to this line  = - 1 / m

so for our line the slope is  - 1 / (1/5)
can you work that out?

anonymous · Answer

umm honestly not really?? ...

cwrw238 · Answer

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