Which of the following is a solution of the compound inequality? 3x + 8 < 2 or x + 12 > 2 - x A. x < -2 or x > 5 B. x < -6 and x > 5 C. All real numbers D. No solution
3x + 8 < 2 3x < 2 - 8 3x < -6 x < -2 x + 12 > 2 - x x + x > 2 - 12 2x > -10 x > -5 so we have x < -2 and x > -5 Is the problem written correctly ?
Yes it is
So is it A
I am not sure, because it states x < -2 or x > -5.
SInce theres no correct answer would it be no solution
not sure....you will need someone who knows more about this to answer it. I am so sorry.
NO worries
@ganeshie8 .....help please
@phi ...can you take a look at this please
@texaschic101 you arrived at the correct answer x < -2 or x > -5 if we plot this on a number line, we get |dw:1389974341107:dw| as you can see one or the other of x<-2 OR x>-5 will be true for all x's (in some cases, both statements are true: example x=-3) The point is we can simplify these two statements to *all real numbers*
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