Mathematics
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OpenStudy (anonymous):
a bag contains 2 green,9 brown, 7 yellow, and 4 blue marbles help with a few of the probabilitys?
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OpenStudy (anonymous):
p(green then blue) p(blue then blue) p(brown then not green)???? and once a marble is selected it is not replaced thank u so much
OpenStudy (anonymous):
what did you do?
OpenStudy (anonymous):
im confused with how to get it for more thn 1
OpenStudy (amoodarya):
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OpenStudy (anonymous):
P(green then blue). what is P(green)?
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OpenStudy (anonymous):
permutation or combination that means
OpenStudy (anonymous):
permutation. Green then blue is different from blue then green
OpenStudy (anonymous):
woulnt it be 6/22 ???
OpenStudy (anonymous):
correct. and because you can not replace the ball that is picked out, how many are left?
OpenStudy (anonymous):
16
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OpenStudy (anonymous):
shouldn't there be 21 balls left? you had 22 initially
OpenStudy (anonymous):
so it would be out of 21?
OpenStudy (anonymous):
wait, why 6/22? what's that?
OpenStudy (anonymous):
green+blue/ all the marbles
OpenStudy (anonymous):
we're looking for P(green), which is 2/22, am correct?
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OpenStudy (anonymous):
green, then blue yes
OpenStudy (anonymous):
P(blue) = 4/21
OpenStudy (anonymous):
yes?
OpenStudy (anonymous):
yes we r finding it foe green, then blue the probability of picking them
OpenStudy (anonymous):
so P(green then blue) = 2/22 * 4/21 <--
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OpenStudy (anonymous):
so 5.25 ah thank u
OpenStudy (anonymous):
you did the math wrong. (2/22) * (4/21) = 0.01731601731
OpenStudy (anonymous):
thx u sm