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Find the solution of the given initial value problem. ty'+4y=t^2-t+5, y(1)=3
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Won't be able to stay on my computer long enough to help you much, but I'd like to point out that this equation could easily be put into the standard form of a first order linear differential equation, and thus solved in that manner.\[\frac{ dy }{ dt }+py=q\]is that standard form. Try rewriting your equation so that it takes on this std. form.
oh ok thank you!
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