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https://media.glynlyon.com/g_geo_2012/11/groupi39.gif Need some help in finding the "y"
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@eliassaab
Which trigonometric ratio relates base and hypotenuse??
I know the ratio, but I need a little help in outlining steps. The trigo ratio is a^2+b^2=c^2
He talking about sine and cos! Not Pythagoras theorem! :) @StrikeEagle
Do you know what cos30 is?
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oh hmm okay Cos - Adjacent/Hypotenuse Sine - Opposite/H Tangent - O/A
yeah 0.5
its easy use AAS theorem and then put values in b/sin B = c/sin C if I am not mistaken
Ok can you just help me solve this? I am using this question as a template to solve other questions
\[\cos30=\sqrt{3}/2\]
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So \[\sqrt{3}/2=7/y\]
Find y first. And then you can use Pythagoras theorem to find x! :)
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