What is the seventh term of the sequence 1, 3, 9, 27, ...?
81
243
729
2187
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OpenStudy (the_fizicx99):
What is 27/9 ?
OpenStudy (anonymous):
3 @tHe_FiZiCx99
OpenStudy (the_fizicx99):
Yes, lol
So what is 9/3 ?
OpenStudy (anonymous):
1 @tHe_FiZiCx99
OpenStudy (the_fizicx99):
9/3 is 1 ??! O_O
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OpenStudy (anonymous):
yes?? @tHe_FiZiCx99
OpenStudy (mathmale):
9 DIVIDED BY 3 IS 1??
OpenStudy (anonymous):
-3??
OpenStudy (mathmale):
Perhaps someone intended that to be a joke and I was too slow to get it. :)
OpenStudy (anonymous):
I got 1
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OpenStudy (anonymous):
81
OpenStudy (the_fizicx99):
No, its 3
and 3/1 is 3 xD so their common ratio is 3
So easily plug in for: f(n) = f(1) • r^n-1,
Plug in any number you want to find, I'll find the 6th term.
f(6) = f(1) • 3^6-1
f(6) = f(1) • 3^5
f(6) = f(1) • 243
3 • 243
f(6) = 729
OpenStudy (anonymous):
a(n) = 3^(n-1) for all real numbers n
OpenStudy (the_fizicx99):
My bad, f(1) = 1
1 * 243 = 243
f(6) = 243
f(7) = 729 lol now there's your answer :#
OpenStudy (mathmale):
larryboxaplenty: Great that you could come up with such an appropriate formula!! As for n values, though, wouldn't the domain be "integers starting with 1", and not "all real n"?