Question

The table below shows some values of f(x) and g(x) for different values of x.

x f(x) = 9x + 7 g(x) = 5x


-2 -11



-1 -2



0 1

1 5

2

Complete the chart and determine the solution of the equation f(x) = g(x)?
x = -1

x = 0

x = 2

x = 25

Answer 1

You can either graph them and put the value at which they intersect OR plug in the x values for all the x's and see which gives you a true statement

For example: 6 = 6 is a true statement, therefore a solution <-- example

Answer 2

how do I plug in whered the -11 and -2 come from where do I figure out the other terms to fill in

Answer 3

Huh?

Answer 4

how am I supposed to fill in the chart

Answer 5

for g(x), where x is -2, put -2 in the equation for g(x)

Answer 6

g(x) = 5x. Put -2 in the equation. 5(-2) = -10

Answer 7

so g(-2) = -10

Answer 8

oh I just notice the 5x has an exponent of x so g(x) = 5x ^x so it would be = 5?

Answer 9

for x=-2

Answer 10

I'm back

Answer 11

5x^x

(-2)^(-2) = -(1/4). 5*(-1/4) = (-5/4)

Answer 12

internet trouble

Answer 13

I cant write a fraction into the table it wouldn't make sense

Answer 14

Why not? (-5/4) = -1.25 if you want to use decimals

Answer 15

can you do the rest yourself?

Answer 16

wait how does -2^-2 equals -1/4 wouldn't it equal 4

Answer 17

An exponent can't be negative it would be 1/-2^2 = 1/4 = 0.25

Answer 18

sorry, it's positive (1/4) for -2^-2

Answer 19

1/(-2)^2

Answer 20

so the answer is (5/4) or 1.25

Answer 21

I just used a calculator and -2^2 = 4

Answer 22

did you put brackets in between -2, like this: (-2)^(-2). if you do -2^-2 on a calculator, it will give you the wrong number.

Answer 23

All I saw is that you were asking if -2^-2 is 4, i said no because an exponent can't be negative, therefore to make it positive you make it 1/-2^2 = 1/4 = 0.25

IF it was -2^2 it is 4 because -2 * -2 = 4 as the two negatives cancel out and make a positive

Answer 24

exactly

Answer 25

ok so if x= -1 I would do 1/-1^1=1 over -1

Answer 26

No, ONLY IF THE EXPONENT IS NEGATIVE

Answer 27

but if x is the exponent and you need to plug in -1 wouldn't the exponent be negative

Answer 28

I don't know what you're trying to solve, but just know that any exponent that is negative must have a 1/a^b to make it positive. From what I see they aren't exponents, 5x and 9x isn't being rasied to any power.. that would be x^5 or x^9

Answer 29

im trying to fill out the table

Answer 30

Screen shot it and make a new question, its too messy. I'll help you

Answer 31

ok