please help with inequalities
x+4<7 => x<7-4 => x<3 so xwill be less than 3 i.e. 2 :)
i believe that number one is b
because if i remember correctly you'd take x+4<7 and then subtract 4 from 4 and from 7 than you get x<3
i believe so. because you HAVE to have one term on each side of the < symbol. and in order to do that you have to subtract the 4 from both sides
i think number 2 is 8
cause first you do distributive property, and distribute x(7-x) and then you get 8<7x-x than you have to add x to x and to 7 and your left with 8<8x
8<x(7-x) 8<7x-x +x +x 8<8x
@AnthonyAnthony Actually in 1: x comes less than 3. so x should be 2 , isn't it?
Nope. i can see how you got that confused because of the < sign. but that sign doesn't make a difference, x<3 is the same as saying x=3.
in 2: yeah it should come 8 , by my openion. see 8<x(7-x) => 8<7x-x^2 Now it is quadretic inequality. Solve it.
@AnthonyAnthony Hmmm :p
no.1 is B
No Prob (:
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