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OpenStudy (anonymous):
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height?
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OpenStudy (anonymous):
Do you have to use the hardcore physics way, or can you just use elementary algebra?
OpenStudy (anonymous):
Algebra is fine!
OpenStudy (anonymous):
Okay, then use the idea that the vertex of a parabola of the form ax^2 + bx + c is -b/(2a).
OpenStudy (anonymous):
In this case, b = 19.6, and a = -4.9.
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