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Mathematics 7 Online
OpenStudy (anonymous):

Find the domain and range of y=x^2 + 2 Answer choices attached inside :) Please explain! Thanks!! :D

OpenStudy (anonymous):

answer choices A,B,C,D from top to bottom :)

OpenStudy (agent0smith):

y=x^2 + 2 What's the domain? Are there any x values you can NOT plug into this function? Huge hint: polynomials have a domain of all real numbers

OpenStudy (anonymous):

ohhh okay.. so is it all real numbers? for the domain?

OpenStudy (agent0smith):

Range: first find the minimum value of y=x^2 + 2

OpenStudy (anonymous):

0^2+2 = 0+2= 2? is that the minimum?

OpenStudy (agent0smith):

Yes

OpenStudy (anonymous):

okay :) so x has to be greater than or equal to 2?

OpenStudy (agent0smith):

Domain for x is all real numbers Range is concerned with y.

OpenStudy (anonymous):

so would this be the correct answer? answer choice A?

OpenStudy (agent0smith):

See above.

OpenStudy (anonymous):

okay thanks!! :D

OpenStudy (agent0smith):

Domain: valid x-values Range: valid y-values

OpenStudy (anonymous):

ohh okay :) i think it's the first choice.. does that look right to you? :)

OpenStudy (agent0smith):

Actually they are ALL wrong. All list the range as x-values. first option is the least wrong, if you changed x to y.

OpenStudy (anonymous):

ohhh okay haha so how would you correctly write the range?

OpenStudy (agent0smith):

2 =< y =< infinity or [2, inf)

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